Question PLEASE HELP!!!! Write the quadratic equation whose graph has x-intercepts of -11 and 3 and passes through the point (1, 192) A: y=8x^2+64x−264 B: y=8x^2−64x−264 C: y=−8x^2+64x+264 D: y=−8x^2−64x+264

The quadratic equation with the given x-intercepts and that passes through the point (1, 192) is the one in option D. y = -8x^2 -64x + 264 What is the quadratic equation? If a quadratic equation has x-intercepts x₁ and x₂ and a leading coefficient a, we can write the quadratic equation as: y = a*(x – x₁)*(x – x₂) Here we know that the x-intercepts are -11 and 3, replacing that in the equation above we will get: y = a*(x + 11)*(x – 3) We also know that the line passes through the point (1, 192), replacing the values in the quadratic equation we will get: 192 = a*(1 + 11)*(1 – 3) 192 = a*12*-2 192 = -24*a 192/-24 = a -8 = a So the quadratic equation is: y = -8*(x + 11)*(x – 3) Expanding this, we will get: y = -8x^2 -64x + 264 So the correct option is D. Learn more about quadratic equations: https://brainly.com/question/1214333 #SPJ1 Reply

quadratic equationwith the givenx-interceptsand that passes through the point (1, 192) is the one in option D.## What is the quadratic equation?

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