Question please help, Solve the system of equations using elimination. −2x + 3y = 13 x + y = 11 (−5, 1) (−3, 3) (3, 8) (4, 7)

-2x + 3y = 13-3(x + y = 11)take the whole bottom equation and multiply by -3 to eliminate the 3y -2x + 3y = 13 -3x -3y = -33cancel out 3y -2x = 13-3x = -33add -2 to -3 and 13 to -33to get -5x = -20divide -5 on both sidesx = 4 then you can do the exact same steps to find the y coordinates, but if x is 4 then the coordinate point is (4,7) Reply

-2x + 3y = 13

-3(x + y = 11)

take the whole bottom equation and multiply by -3 to eliminate the 3y

-2x + 3y = 13

-3x -3y = -33

cancel out 3y

-2x = 13

-3x = -33

add -2 to -3 and 13 to -33

to get -5x = -20

divide -5 on both sides

x = 4

then you can do the exact same steps to find the y coordinates, but if x is 4 then the coordinate point is (4,7)