PLEASE HELP!! I will mark the brainliest!

The perimeter of a rectangle is 56 cm. The length of the rectangle is 2 cm more than the width. Find the dimensions of the rectangle.

Length: ____

Width: ____

The perimeter of a rectangle is 56 cm. The length of the rectangle is 2 cm more than the width. Find the dimensions of the rectangle.

Length: ____

Width: ____

Answer:Rectangles! Nice.

Step-by-step explanation:This is a very simple problem. Let’s first represent the width of the rectangle as the variable x.

Then, we know that the length of the triangle is x+2. See where I’m going with this?

The formula for the perimeter of an rectangle is [tex]P=2*Length+2*Width[/tex].

All we have to do next is just input our values for the length and width, and you’ll be golden!

[tex]56=2(x+2)+2(x)\\56=4x+4[/tex]

Next to subtract 4 from both sides and then to divide by 4!

[tex]52=4x\\x=13[/tex]

There’s your answer! Don’t know why Brainly is bugged right now.

NOTE: If you can’t read the answer above, the width is 13cm. This also means that the length is 15cm.

Hope this helps!

Stay safe!