Question PLEASE HELP! I WILL GIVE 50 POINTS!!! A radar gun measured the speed of a baseball at 92 miles per hour. If the baseball was actually going 90.3 miles per hour, what was the percent error in this measurement?

1.883% error [tex] | \frac{actual – guess}{actual} | \\ | \frac{90.3 – 92}{90.3} | = \frac{1.7}{90.3} = .0188 = .0188 \times 100\% = 1.88\%[/tex] Log in to Reply

Answer: Step-by-step explanation: A radar gun measured the speed of a baseball at 103 miles per hour. If the baseball was actually going 102.8 miles per hour. Log in to Reply

1.883%error[tex] | \frac{actual – guess}{actual} | \\ | \frac{90.3 – 92}{90.3} | = \frac{1.7}{90.3} = .0188 = .0188 \times 100\% = 1.88\%[/tex]