Question

PLEASE HELP I’ll GIVE U BRAINLIEST

Find each function value specified below. Show your work!

1) f(x) = 7x – 3, find F(-2), f(4), and f(O)

2) g(x) = 5 – 2x, find g(-3), g(0) and g(1)

3) h(x) = 8 + 3x, find h(-2), h(4), and h(0)

4) k(x) = 9x – 16, find k(-1), K(0), and k(5)

5) A(x) = – 6x + 2, find A(-3), A(0), and A(7)

6) T(x) = 11x + 4, find T(-1), T(4), & T(0)

Answers

  1. Answer:
    1) f(x) = 7x – 3, find F(-2), f(4), and f(O)
    • f(-2) = 7(-2) – 3
      f(-2) = -14 – 3
      f(-2) = -17
    • f(4) = 7(4) – 3
      f(4) = 28 – 3
      f(4) = 25
    • f(0) = 7(0) –  3
      f(0) = 0 -3
      f(0) = -3
    2) g(x) = 5 – 2x, find g(-3), g(0) and g(1)
    • g(-3) = 5 – 2(-3)
      g(-3) = 5 – (-6)
      g(-3) = 5 + 6
      g(-3) = 11
    • g(0) = 5 – 2(0)
      g(0) = 5 – 0
      g(0) = 5
    • g(1) = 5 – 2(1)
      g(1) = 5 – 2
      g(1) = 3
    3) h(x) = 8 + 3x, find h(-2), h(4), and h(0)
    • h(-2) = 8 + 3(-2)
      h(-2) = 8 – 6
      h(-2) = 2
    • h(4) = 8 + 3(4)
      h(4) = 8 + 12
      h(4) = 20
    • h(0) = 8 + 3(0)
      h(0) = 8 + 0
      h(0) = 8
    4) k(x) = 9x – 16, find k(-1), K(0), and k(5)
    • k(-1) = 9(-1) – 16
      k(-1) = -9 – 16
      k(-1) = 25
    • k(0) = 9(0) – 16
      k(0) = 0 – 16
      k(-1) = -16
    • k(5) = 9(5) – 16
      k(5) = 45 – 16
      k(5) = 29
    5) A(x) = – 6x + 2, find A(-3), A(0), and A(7)
    • A(-3) = -6(-3) + 2
      A(-3) = 18 + 2
      A(-3) = 20
    • A(0) = -6(0) + 2
      A(0) = 0 + 2
      A(0) = 2
    • A(7) = -6(7) + 2
      A(7) = -42 + 2
      A(7) = -40
    6) T(x) = 11x + 4, find T(-1), T(4), & T(0)
    • T(-1) = 11(-1) + 4
      T(-1) = -11 + 4
      T(-1) = -7
    • T(4) = 11(4) + 4
      T(4) = 44 + 4
      T(4) = 48
    • T(0) = 11(0) + 4
      T(0) = 0 + 4
      T(0) = 4

    All you must do to solve these problems are to put the given numbers in place of x and solve the multiplication, addition, and subtraction.
    For example, in given problem T(4), 4 replaces the x both in the parenthesis next to the T and next to the 11.

    I hope this helps.

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