PLEASE HELP 20 points
Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the
with F2 at 280. K and 1.50 atm.
F2 + 2NaCl → Cl2 + 2NaF
Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP
n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl
NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl
58.44g NaCl x .98 mol NaCl = 57.27g NaCl
Explanation:
hope you get it right 🙂