Question pipe A can fill a tank in 3 hours. if pipe B can fill the same tank in 2 hours, how many minutes will it take both pipes to fill 2/3 of the tank

Answer: 48 minutes Step-by-step explanation: The rate of filling from both pipes is the sum of the rates in units of tanks per hour. We want the time for 2/3 of a tank. Sum of rates The sum of the filling rates is … rate A + rate B = (1/3) tank/hour + (1/2) tank/hour = 5/6 tank/hour Fill time The time to fill a tank or part thereof will be the number of tanks divided by the rate in tanks per hour: time = (2/3 tank)/(5/6 tank/hour) = ((4/6)/(5/6)) hour = 4/5 hour There are 60 minutes in an hour, so the fill time is … (4/5 hour)×(60 min/hour) = 48 min It will take 48 minutes for both pipes to fill 2/3 of the tank. Reply

Answer: pipe A =3. pipe B=2 find LCM of 3 and 2 . it will be 6 . Then take 6×2/3 it will give you 4 minutes as the answer Reply

Answer:Step-by-step explanation:rate of fillingfrom both pipes is thesum of the ratesin units of tanks per hour. We want the time for 2/3 of a tank.## Sum of rates

## Fill time

It will take 48 minutes for both pipes to fill 2/3 of the tank.Answer: