physics
Joseph Jogs from one end A to the other end B of a straight
300m road in 2 minutes 30 second then turns around and jogs 100 m back to point C in another minute. What are Josef’s Average speeds and velocities in jogging from
a) A to B
and
b) A to C
pls give answer with explination do not send link
Answer:
a) Josef jogging from A to B;
i. speed = 2 m/s
ii. velocity = 2m/s
a) a) Josef jogging from A to C;
speed = 1.9 m/s
ii. velocity = 2.2 m/s
Step-by-step explanation:
One major difference between speed and velocity is that speed is a scalar quantity, while velocity is a vector quantity.
a) Josef jogging from A to B;
distance = 300 m
time = 2.5 seconds = 150 seconds
i. his average speed = [tex]\frac{distance}{time}[/tex]
= [tex]\frac{300}{150}[/tex]
= 2 m/s
ii. his average velocity = [tex]\frac{displacement}{time}[/tex]
= [tex]\frac{300}{150}[/tex]
= 2 m/s
b) Josef jogging from A to C,
distance = 300 + 100 = 400 m
time = 2.5 + 1 = 3.5 minutes
= 210 seconds
i. his average speed = [tex]\frac{distance}{time}[/tex]
= [tex]\frac{400}{210}[/tex]
= 1.9 m/s
ii. his average velocity = [tex]\frac{\sqrt{V_{1} ^{2} + V_{2} ^{2} } }{2}[/tex]
[tex]V_{1} ^{2}[/tex] = 4 m/s
[tex]V_{2} ^{2}[/tex] = 1.9 m/s
his average velocity = [tex]\frac{\sqrt{4^{2} + 1.9^{2} } }{2}[/tex]
= 2.2 m/s