pH de un jugo de naranja con [H+]=5.6×10-4M. August 25, 2021 by Thành Đạt pH de un jugo de naranja con [H+]=5.6×10-4M.
Explanation:
[tex]pH = – log[H {}^{ + } ] \\ = – log(5.6 \times {10}^{ – 4} ) \\ = 3.25[/tex]