On a standardized exam, the scores are normally distributed with a mean of 200 and a standard deviation of 40. Find the z-score of a person who scored 292 on the exam.

Answers

The z-score of a person who scored 292 on the exam is 2.30

How to determine the z-score?

The given parameters are:

Scores are normally distributed

Mean of 200

Standard deviation of 40

The z-score of a person who scored 292 on the exam is calculated as:

z = Score – mean/Standard deviation

So, we have

z = 292 – 200/40

Evaluate the difference

z = 92/40

Divide

z = 2.30

Hence, the z-score of a person who scored 292 on the exam is 2.30

z-scoreof a person whoscored 292on the exam is 2.30## How to determine the z-score?

z-scoreof a person whoscored 292on the exam is calculated as:z-scoreof a person whoscored 292on the exam is 2.30z-scoresat: