Question

On a standardized exam, the scores are normally distributed with a mean of 200 and a standard deviation of 40. Find the z-score of a person who scored 292 on the exam.

Answers

  1. The z-score of a person who scored 292 on the exam is 2.30

    How to determine the z-score?

    The given parameters are:
    • Scores are normally distributed
    • Mean of 200
    • Standard deviation of 40
    The z-score of a person who scored 292 on the exam is calculated as:
    z = Score – mean/Standard deviation
    So, we have
    z = 292 – 200/40
    Evaluate the difference
    z = 92/40
    Divide
    z = 2.30
    Hence, the z-score of a person who scored 292 on the exam is 2.30
    Read more about z-scores at:
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