Of all the people at a community swimming pool, 54 are in the water and 66 are not in the water. What percentage of the people at

Of all the people at a community swimming pool, 54 are in the water and 66 are not in the water. What percentage of the people at the pool are in the water?

10%

45%

82%

55%

2 thoughts on “Of all the people at a community swimming pool, 54 are in the water and 66 are not in the water. What percentage of the people at”

  1. The percentage of people at the pool and in the water is a representation of the fraction of people in the water to the total people at the pool, written like this.

    people in water / total people at the pool

    Substituting the given numbers:

    54 / (54 + 66)

    54 / 120

    Solve the fraction and multiply by 100 to find the percentage:

    54 / 120 = 0.45 x 100 = 45%

    Let me know if you have any questions!

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  2. Answer: 45%.
    Step-by-step explanation: When you solve problems like these, you need to make the total 100%.  The total amount of people at the community pool is 120.  120 can be our 100%.  66 people aren’t in the water and 54 are in the water.  As you can see, less than half of the total number of people at the community swimming pool is in the water, which means that is 45%.  The 66 people who aren’t in the water are 55% of the total people that are at the community swimming pool.  So in summary, 45% of the total people who are in the community swimming pool are in the water.
    Have a great day! 🙂

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