NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find the number of bit strings that satisfies the given conditions. The bit strings of length 7 having at least four 1s

Answers

64 is the number of bit strings that are of length 7 having at least four 1s. This can be obtained by finding each of the required combination and adding them.

Find the number of required bit strings:

Bit: Bit is a digit which is either zero or one.

Bit string: Bit string is a string of bits. A bit string is a string that contains 0 and 1 only.

Byte: Byte is a string of 8 bits.

If length of the string is n, then there are 2ⁿ bit stings of length n.

We apply combination formula for this,

⇒ ⁿCr = n!/(n-r)!r!

At least four 1s is 4, 5, 6, 7,

⇒ ⁷C₄ + ⁷C₅ + ⁷C₆ + ⁷C₇ = 35 + 21 + 7 + 1

⇒ ⁷C₄ + ⁷C₅ + ⁷C₆ + ⁷C₇ = 64

Hence 64 is the number of bit strings that are of length 7 having at least four 1s.

64is the number of bit strings that are of length7having at least four 1s. This can be obtained by finding each of the requiredcombinationandaddingthem.## Find the number of required bit strings:

Bit:Bit is a digit which is either zero or one.Bit string:Bit string is a string of bits. A bit string is a string that contains 0 and 1 only.Byte:Byte is a string of 8 bits.2ⁿbit stings of length n.6464is the number of bit strings that are of length 7 having at least four 1s.bit stringhere: