Need assistance with this question any help is appreciated 1)write the equation of the line through (4,-1) that is perpendicular t

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Need assistance with this question any help is appreciated 1)write the equation of the line through (4,-1) that is perpendicular to the line 2x – y = 4.
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  1. The equation of line become y = (-x/2) + 3.
    According to the statement
    We have to find the equation of the line from the given details.
    So, For this purpose, we know that the
    Point slope form is that the equation of a line within the form y − y1 = m(x − x1) where m is that the slope of the road and (x1, y1) are the coordinates of a given point on the road.
    Then
    Here, we are required to search out the equation of the road that passes through the purpose (4,1) and is
    perpendicular to the road 2x – y = 4.
    The equation of the road is: y = (-x/2) + 3
    First, the merchandise of the slopes of two perpendicular lines is -1.
    Therefore, M1 × M2 = -1.
    By rearranging the equation 2x – y = 4 to mimic the equation of a straight line; y = mx + c.
    we have, y = 2x + 4 and clearly slope, m1 = 2.
    Therefore, since M2 = -1/M1 from above;
    M2 = -1/2
    Therefore, the equation of the specified line is given by;
    M2 = (y – y1)/(x – x1)
    where, M2 = -1/2, y1 = 1 and x1 = 4.
    Ultimately, -1/2 = (y – 1)/(x – 4)
    The equation of the line is then given as;
    y = (-x/2) + 3.
    Hence, The equation of line become y = (-x/2) + 3.
    Learn more about Point slope form here
    #SPJ9

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