Answers

1. standard form of the given equation are

   -f(*) = (x + 2)(x – 6) = x² – 4x – 12

   f(x) = (x – 4)(x + 3) = x² – x – 12

   f(x) = (x – 12)(x + 1) = x² – 11x – 12

   f(x) = (x -3)(x + 4) = x² + x – 12

   What is quadratic function?

   A polynomial function with one or more variables in which the second-degree term is the highest degree is known as a quadratic function, quadratic polynomial, polynomial of degree 2, or simply a quadratic, in algebra.

   What is standard form of a quadratic function?

   As long as an is not equal to zero, the quadratic function f(x) = a(x – h)2 + k is considered to be in standard form. The graph starts out in either an upward or a downward direction depending on the value of a. The point at the vertex of the symmetry is represented by the vertical line x = h. (h,k).

   According to the given information:

   The standard form list.

   1 .   (x + 2)(x – 6)

   = x² – 6x + 2x – 12

   =  x² – 4x -12

   2.  (x – 4)(x + 3)

       = x² + 3x – 4x – 12

      =   x² – x – 12

   3. (x – 12)(x + 1)

       = x² + 1x – 12x – 12

       =  x² – 11x – 12

   4.  (x -3)(x + 4)

       =   x² + 4x – 3x – 12

        = x² + x – 12

   So the equivalent standard form  of the give values are :

   -f(*) = (x + 2)(x – 6) = x² – 4x – 12

   f(x) = (x – 4)(x + 3) = x² – x – 12

   f(x) = (x – 12)(x + 1) =  x² – 11x – 12

   f(x) = (x -3)(x + 4) = x² + x – 12

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   I understand that the question you are looking for is:

   Match each quadratic function given in factored form

   with its equivalent standard form listed on the left.

   f(x) = (x + 2)(x – 6)

   f(x) = (x – 4)(x+3)

   f(x) = (x – 12)(x+1)

   f(x) = (x – 3)(x +4)

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