Question In ΔTUV, the measure of ∠V=90°, the measure of ∠U=85°, and VT = 20 feet. Find the length of TU to the nearest tenth of a foot.

Answer: 20.1 Step-by-step explanation: sinU= hypotenuse opposite = x 20 \sin 85=\frac{20}{x} sin85= x 20 x\sin 85=20 xsin85=20 Cross multiply. \frac{x\sin 85}{\sin 85}=\frac{20}{\sin 85} sin85 xsin85 = sin85 20 Divide each side by sin 85. x=\frac{20}{\sin 85}=20.0764\approx 20.1\text{ feet} x= sin85 20 =20.0764≈20.1 feet Type into calculator and roundto the nearest tenth of a foot. T U V 20 20.1 (opposite of ∠U) (adj. to ∠U) (hypotenuse) 85° Log in to Reply

Answer: 20.1 Step-by-step explanation: I if you are here from delta math this is the answer Log in to Reply

Answer: 20.1Step-by-step explanation:sinU=

hypotenuse

opposite

=

x

20

\sin 85=\frac{20}{x}

sin85=

x

20

x\sin 85=20

xsin85=20

Cross multiply.

\frac{x\sin 85}{\sin 85}=\frac{20}{\sin 85}

sin85

xsin85

=

sin85

20

Divide each side by sin 85.

x=\frac{20}{\sin 85}=20.0764\approx 20.1\text{ feet}

x=

sin85

20

=20.0764≈20.1 feet

Type into calculator and roundto the nearest tenth of a foot.

T

U

V

20

20.1

(opposite of ∠U)

(adj. to ∠U)

(hypotenuse)

85°

Answer: 20.1

Step-by-step explanation: I if you are here from delta math this is the answer