Question

In triangle ABC, <A and <B are complementary, where cos A=0.68. What is the value of the sine of angle B? ​

Answers

1. ngochoa
Answer:
sin B = 0.68
Step-by-step explanation:
sin(angle) = cos(complement)
since ∠ A and ∠ B are complementary , then
sin B = cos A = 0.68

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