In triangle ABC,

Question

In triangle ABC, <A and <B are complementary, where cos A=0.68. What is the value of the sine of angle B? ​

ngochoa · Answer

Answer:   sin B = 0.68   Step-by-step explanation:   sin(angle) = cos(complement)  since ∠ A and ∠ B are complementary , then  sin B = cos A = 0.68