Question In triangle ABC, <A and <B are complementary, where cos A=0.68. What is the value of the sine of angle B?

Answer: sin B = 0.68 Step-by-step explanation: sin(angle) = cos(complement) since ∠ A and ∠ B are complementary , then sin B = cos A = 0.68 Reply

Answer:Step-by-step explanation: