Question In ΔIJK, i = 74 inches, j = 23 inches and ∠K=20°. Find the area of ΔIJK, to the nearest square inch.

Answer: 291in^2 Step-by-step explanation: Using the formula Area of the triangle = 1/2absin theta A = 1/2ijsin<K Given i = 74in j = 23in <K = 20 degrees Area = 1/2 * 74*23sin20 Area = 37*23sin20 Area = 852sin20 Area = 291.059in^2 Hence the area of the triangle to nearest square inch is 291in^2 Reply

Answer:291in^2Step-by-step explanation:Using the formula

Area of the triangle = 1/2absin theta

A = 1/2ijsin<K

Given

i = 74in

j = 23in

<K = 20 degrees

Area = 1/2 * 74*23sin20

Area = 37*23sin20

Area = 852sin20

Area = 291.059in^2

Hence the area of the triangle to nearest square inch is 291in^2