Question

In an animal shelter with $30$ animals, each of which is either a cat or a dog, $12$ out of $15$ dogs have long fur and $11$ out of $15$ cats have long fur. what is the probability that in a randomly selected group of five animals from the shelter, there will be two long-furred dogs and three long-furred cats? express your answer as a decimal to the nearest thousandth.

Answers

  1. The probability that there will be two long-furred dogs and three long-furred cats will be 0.2728.

    How to calculate the probability?

    Number of animals = 30
    Number of dogs with long fur = 12/15 = 0.8
    Number of cats with long fur = 11/15 = 0.73
    The probability that there will be two long-furred dogs and three long-furred cats will be:
    = (0.8)³ × (0.73)²
    = 0.512 × 0.5339
    = 0.2728
    Therefore, the probability that there will be two long-furred dogs and three long-furred cats will be 0.2728.
    Learn more about probability on:
    brainly.com/question/24756209
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