In AMNO, m = 41 cm, o = 98 cm and Angle O=22º. Find all possible values of Angle M, to the nearest degree.
Answer:
Answer:
85t
Step-by-step explanation:
1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))
Answer:
Answer:
85t
Step-by-step explanation:
1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))
hope this helps
Answer:
9
Step-by-step explanation:
sin(M)/41 = sin(22)/98
sin(M)=41sin(22)/98 = 0.1567232
sin^-1(0.1567232) = 9.02 = 9