In 1995, the moose population in a park was measured to be 1800. By 1998, the population was measured again to be 2400. If the population continues to change linearly:

Find a formula for the moose population,

P

, in terms of

t

, the years since 1990.

linearequation for thevariationof population isp = 200t + 1800.## What is an equation?

equationis defined as therelationbetween twovariables, if we plot the graph of thelinearequation we will get astraightline.formulafor an equation ininterceptform will begivenas below:-giventhat In1995, the moosepopulationin a park wasmeasuredto be1800. By 1998, thepopulationwas measured again to be2400.linearequation forpopulationvariation.Rateof change = ( 2400 – 1800 ) / 3 = 200, put thevaluein the equation.valuesin theequationto get thevalueof the constant.equationfor thelinearvariation of thepopulationis,linearequation for thevariationof thepopulationisp = 200t + 1800.equationsfollow