(II) A baseball pitcher throws a baseball with a speed of 43 m????s. Estimate the average acceleration of the ball during the throwing motion. In throwing the baseball, the pitcher accelerates it through a displacement of about 3.5 m, from behind the body to the point where it is released
Question
Answer:
a = 264.14 m/s²
Explanation:
From the question;
Initial velocity; u will be 0 m/s since the ball will start from rest.
Final velocity; v = 43 m/s
distance covered by the motion; s = 3.5m
To get the acceleration, we will make use of Newton’s third equation of motion which is;
v² = u² + 2as
Making a the subject, we have;
a = (v² – u²)/2s
Plugging in the relevant values to give;
a = (43² – 0)/(2 × 3.5)
a = 264.14 m/s²