Question if you have an unfair coin with probability p heads, what is the expected number of flips before you end up with a head?

The scenario assumed to be the number of flips until you land on a head is P(x) = 1 + (1 – p)/p. Given info, If you have an unfair coin with probability p heads, what is the expected number of flips before you end up with a head, To solve the above condition, have a formula; P(x) = 1 + ( 1 – p )/p Hence, P(x) = 1 + ( 1 – p )/p is the case expected to number of flips before you end up with a head. To learn more about probability click here: brainly.com/question/11234923 #SPJ4 Log in to Reply

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