Question

If you flipped two coins simultaneously, for a total of 24 times, how many times, on average, would you expect to get a head and a tail?

1. When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.
For given question,
When two coins are tossed simultaneously, the sample space is as follows:
S = { HH, HT, TH, TT} where H denotes Head and T denotes tail.
Using the formula of probability,
P = Number of favorable outcomes/total number of outcomes,
we get,
P(HT) = 1/4
and
P(TH) = 1/4
We know that the occurrence of two mutually exclusive events is the sum of their individual probabilities.
So, P(Head on one and Tail on other)
= P(HT) + P(TH)
= 1/4 + 1/4
= 2/4
= 1/2
= 0.5
So, when two coins flipped simultaneously, the probability of flipping 2 coins and getting a head and a tail is 0.5
In this question, we need to find the number of times getting a head and a tail when two coins are flipped simultaneously 24 times
= 0.5 × 24
= 12
Therefore, When two coins are flipped simultaneously 24 times, on average 12 times we will get a head and a tail.