. If R1 = {(x, y)| y = 2x + 7, where x∈ R and -5 ≤ x ≤ 5} is a relation. Then find the domain and range of R1. August 2, 2021 by RuslanHeatt . If R1 = {(x, y)| y = 2x + 7, where x∈ R and -5 ≤ x ≤ 5} is a relation. Then find the domain and range of R1.

Answer: Domain is [-5, 5] Range is [-3, 17] Step-by-step explanation: R1 = {(x, y)| y = 2x + 7, where x∈ R and -5 ≤ x ≤ 5} The domain is given by the all possible input values of x . Here the function is defined for -5 ≤ x ≤ 5, so the domain is [ – 5, 5]. The range is given by the output values of he function. When x = – 5 f (- 5) = 2 (-5 ) + 7 = – 3 When x = 5 f (5) = 2 (5) + 7 = 17 So, the range is [ -3 , 17]. Reply

Answer:Domain is [-5, 5]

Range is [-3, 17]

Step-by-step explanation:R1 = {(x, y)| y = 2x + 7, where x∈ R and -5 ≤ x ≤ 5}

The domain is given by the all possible input values of x . Here the function is defined for -5 ≤ x ≤ 5, so the domain is [ – 5, 5].

The range is given by the output values of he function.

When x = – 5

f (- 5) = 2 (-5 ) + 7 = – 3

When x = 5

f (5) = 2 (5) + 7 = 17

So, the range is [ -3 , 17].