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1. The probability that I will end up with one card from each suit is 3/32 when I choose four cards from a standard-card deck, with replacement. This can be obtained by finding probability of each draw.

   What is the required probability?

   • The probability of drawing first card is one, that is the card can be of any suite.

   • The probability of drawing second card is,      

   ⇒ 52 cards – 13 cards (1 suite) = 39 cards (remaining 3 suites)

   On the second draw, we have a (39/52)  = (3/4)  probability of drawing a different suite from the first draw

   • The probability of drawing third card is,

   ⇒ 52 cards – 26 cards (2 suite) = 26 cards (remaining 2 suites)

   On the third draw we have a (26/52) = (1/2) probability of drawing a suite different from the first two draws

   • The probability of drawing fourth card is,

   ⇒ 52 cards – 39 cards (3 suite) = 13 cards (remaining 1 suites)

   On the last draw we  have a (13/52) = (1/4) probability of drawing a different suite from the ones we  drew on the first three draws

   So  the probability = (1) (3/4) (1/2) (1/4) = 3/32

   Hence the probability that I will end up with one card from each suit is 3/32 when I choose four cards from a standard-card deck, with replacement.

      

   Learn more about probability here:

   brainly.com/question/17058636

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