Question If a polynomial function, f(x), with rational coefficients has roots 3 and startroot 7 endroot, what must also be a root of f(x)?

The conjugate which is 3 – √7 is also a root of f(x). What is the root of a polynomial function? The root of a polynomial function f(x) is the value of x for which f(x) = 0. Now if a polynomial function has a root x = a + √b then the conjugate of x which is x’ = a – √b is also a root of the function, f(x). What must also be a root of f(x)? Given that the polynomial function, f(x), with rational coefficients has roots 3 + √7, then by the above, the conjugate which is 3 – √7 is also a root of f(x). So, 3 – √7 is also a root of f(x). Learn more about root of a polynomial function here: https://brainly.com/question/2833285 #SPJ1 Reply

3 – √7is also arootof f(x).## What is the root of a polynomial function?

rootof apolynomial function f(x)is the value of x for which f(x) = 0.x = a + √bthen the conjugate of x which isx’ = a – √bis also arootof thefunction, f(x).## What must also be a root of f(x)?

polynomial function, f(x), with rational coefficients has roots3 + √7,then by the above, the conjugate which is3 – √7is also a root of f(x).3 – √7is also arootof f(x).rootof apolynomial functionhere: