if a humane society has 73 dogs and cats to be adopted. the number of cats is 10 more than twice the number of dogs. how many of each animal is up for adoption

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Let D be the number of dogs up for adoption and C be the number of cats up for adoption. We can set up the following equation to represent the problem:

D + C = 73

C = 2D + 10

Substituting the second equation into the first equation, we get:

D + 2D + 10 = 73

3D + 10 = 73

3D = 63

D = 21

Substituting this back into the second equation, we find that C = 2 * 21 + 10 = 52.

Therefore, there are 21 dogs and 52 cats up for adoption.