If a firework is launched vertically upwards from a height of 20 feet above the ground. Its path is give by h(t)=-4t+16t+20, where h is the height of feet and t is the time in seconds.

can someone help me find the right answers for this with scratch work? i’m struggling quite a bit.

when is the firework at max height?

What was the highest point that the firework reached?

What is the starting point of the firework?

How high is the firework after 3 seconds?

When does the firework hit the ground?

timeof the maximum height is of 2 seconds.maximum heightof the firework is of 36 feet.starting pointof the firework is of 20 feet.3 seconds,the firework is at a height of 32 feet.hits the groundafter 5 seconds.## What is the quadratic function?

heightof the firework in this problem after t seconds is given as follows:starting pointof the firework, as follows:3 secondsis calculated with the numeric value as follows:coefficientsof the quadratic function are given as follows:vertexis amaximumpoint.t-coordinateof the vertex is given as follows:maximum heightof the firework is of:hits the groundwhen h(t) = 0, hence, using a quadratic function calculator, the time is of:quadratic functionsat https://brainly.com/question/24737967