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1. The probability of flipping at least two heads in a row is 3/8.

   Let E be an event of flipping atleast two heads in a row.

   According to the given question.

   A fair coin is flipped three times.

   Therefore,

   The sample space when a fair coin is flipped three times is

   {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

   Where, H denotes of getting H and T denotes getting tail.

   So, there is total eight possible outcomes we get when a fair coin is flipped.

   Now, the total possible sequences or outcomes of getting or flipping atleast two heads in a row would be {HHH, HHT, THH}

   ⇒ Total number of favorable outcomes = 3

   Therefore, the probability of flipping at least two heads in a row is given by

   P(E) = number of favorable outcomes/total number of outcomes

   ⇒ P(E) = 3/8

   Hence, the probability of flipping at least two heads in a row is 3/8.

   Find out more information about probability here:

   https://brainly.com/question/11234923

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