if a current flowing through a lightbulb is 0.75 ampere and the voltage differences across the lightbulb is 120 volts how much resistance does the lightbulb have

We have the equation I = V/R ( according to ohm’s law ==> R = V / I ==> R = 120/0.75 ==> R = 160 ohms *I is current ( unit : ampere) *V is voltage different and R is resistance

We have the equation I = V/R ( according to ohm’s law

==> R = V / I

==> R = 120/0.75

==> R = 160 ohms

*I is current ( unit : ampere)

*V is voltage different and R is resistance