Question

If 5.60 mol of a substance releases 14.9 kJ when it decomposes, what is ΔH for the process in terms of kJ/mol of reactant?

Answers

  1. Answer:

    The correct approach is “-2.67 kJ/mole“. A further solution is described below.

    Explanation:

    The given values are:

    No. of moles,

    = 5.60 mol

    Substance releases,

    ΔH = 14.9 kJ

    Now,

    The ΔH in terms of kJ/mol will be:

    = \frac{\Delta H}{5.60}

    On putting the given values of ΔH, we get

    = \frac{-14.9}{5.60}

    = -2.67 \ kJ/mole

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