If (3y-9)^2+7=43, then what is(are the values of y?

Question

If (3y-9)^2+7=43, then what is(are the values of y?​

Neala · Answer

Answer:   y=5   Step-by-step explanation:   (3y-9)(3y-9)=36  apply a foil method  9y^2-54y+81-36=0  9y^2-54y+45=0   quadratic formula  y=5 / y=1  substitute y=5 on the equation  9(5)^2-54(5)+45=0

giabao · Answer

Answer:   y = 1 and y = 5   Step-by-step explanation:   ( 3 y -9)^2 + 7 = 43    ((3y)^2 + (-9)^2 + 2(3y)(-9)) = 43 - 7    (9y^2 + 81 -54y) = 36    9y^2 -54y + 81 -36 = 0    9y^2 -54y + 45 = 0    9(y^2 -6y + 5) = 0    y^2 - 6y + 5 = 0    y^2 - 5y - y + 5 = 0    y(y - 5) -1(y - 5 ) = 0     ( y - 1 )( y - 5) = 0    y = 1   ,   y = 5

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