Question

How would you describe the relationship between the real zero(s) and x-intercept(s) of the
function f(x) =
3x(x-1)
x²(x+3)(x+1)
When you set the function equal to zero, the solution is x = 1; therefore, the graph has an x-intercept of (1, 0).
O When you set the function equal to zero, the solutions are x = 0 or x = 1; therefore, the graph has x-intercepts at
(0, 0) and (1, 0).
O When you substitute x = 0 into the function, there is no solution; therefore, the graph will not have any x-intercepts.
O Since there are asymptotes at x = -3, x=-1, and x = 0, the graph has no x-intercepts and, therefore, no real
zeros.

1. The description of the relationship between the real zero(s) and x-intercept(s) of the function should be option A.
What is function?
A function in mathematics from a set X to a set Y allocates precisely one element of Y to each element of X. The sets X and Y are collectively referred to as the function’s domain and codomain, respectively.
Relationship between the real zero(s) and x-intercept(s) of the function:
Since it is given that
f(x) = 3x(x – 1)
x2(x+3)(x + 1)
Also, the function should be set out and equivalent to zero when x = 1
and, the graph should have an x-intercept of (1,0).
Therefore, the option A is correct.