Question How to write the equation of the line that goes through (4, –6) and (1, 2) answer in Slope–Intercept Form.

Answer: Step-by-step explanation: To write the equation of the line that goes through the points (4, -6) and (1, 2) in slope-intercept form, we can use the slope-intercept form of a linear equation: y = mx + b. To find the slope of the line, we can use the formula: m = (y2 – y1) / (x2 – x1) Plugging in the values, we get: m = (2 – (-6)) / (1 – 4) = 8 / -3 = -2.67 The slope of the line is therefore -2.67. Now that we know the slope of the line, we can use the point-slope form of a linear equation to find the equation of the line: y – y1 = m(x – x1) Plugging in the values, we get: y – (-6) = (-2.67)(x – 4) We can then simplify the equation by combining like terms: y + 6 = -2.67x + 10.67 Finally, we can rewrite the equation in slope-intercept form by solving for y: y = -2.67x + 16.67 So the equation of the line that goes through (4, -6) and (1, 2) in slope-intercept form is y = -2.67x + 16.67. I hope this helps! Let me know if you have any questions. Reply

Answer: y= -8/3x + 14/3 Step-by-step explanation: Slope–Intercept Form is y= mx + b We see that the y increased by 8 and the x decreased by 3, so our slope is -8/3 The y-intercept is located at 14/3 So our answer is y= -8/3x + 14/3 Reply

Answer:Step-by-step explanation:Answer: y= -8/3x + 14/3Step-by-step explanation: