Explanation: We will use the formula for heat to solve this problem Q= mc∆T, where the specific heat or “c” of water is 4200 J/kg°C. The change in temperature ∆T is equal to ∆T = ( 75°C-25°C) = 50°C

Q= 4.0 kg ( 4200 J/kg°C) ( 50°C)

= 840,000J

Cancel out the units of kg and °C so the remaining unit is in joules.

Answer:313.5 joule thermal energy is required

Answer: Q= 840,000 J

Explanation: We will use the formula for heat to solve this problem Q= mc∆T, where the specific heat or “c” of water is 4200 J/kg°C. The change in temperature ∆T is equal to ∆T = ( 75°C-25°C) = 50°C

Q= 4.0 kg ( 4200 J/kg°C) ( 50°C)

= 840,000J

Cancel out the units of kg and °C so the remaining unit is in joules.