Explanation: We will use the formula for heat to solve this problem Q= mc∆T, where the specific heat or “c” of water is 4200 J/kg°C. The change in temperature ∆T is equal to ∆T = ( 75°C-25°C) = 50°C
Q= 4.0 kg ( 4200 J/kg°C) ( 50°C)
= 840,000J
Cancel out the units of kg and °C so the remaining unit is in joules.
Answer:
313.5 joule thermal energy is required
Answer: Q= 840,000 J
Explanation: We will use the formula for heat to solve this problem Q= mc∆T, where the specific heat or “c” of water is 4200 J/kg°C. The change in temperature ∆T is equal to ∆T = ( 75°C-25°C) = 50°C
Q= 4.0 kg ( 4200 J/kg°C) ( 50°C)
= 840,000J
Cancel out the units of kg and °C so the remaining unit is in joules.