How much energy does a copper sample absorb as heat if its specific heat is 0.384 J/g.°C, its mass is 8.00 g, and it is
heated from 10.0°C to 40.0°C?

Answer:

.0016

Explanation:

For specific heat problems you use the formula :

Q = mcΔT

They’ve given you the m, c and delta T, so you can plug in those values. (for the temperature change subtract 10 from 40 to see that it grew 30 degrees)

You’re looking for Q so leave that variable in the equation. Then solve.

Answer:.0016

Explanation:For specific heat problems you use the formula :

Q = mcΔT

They’ve given you the m, c and delta T, so you can plug in those values. (for the temperature change subtract 10 from 40 to see that it grew 30 degrees)

You’re looking for Q so leave that variable in the equation. Then solve.

.Q = (8.00)(.384)(30)

Q = 92.16