How many ways are there to construct a string of 3 digits from the decimal numbering system if the numbers cannot be repeated
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There are total 720 ways according to the permutation by which construct a string of 3 digits from the decimal numbering system.According to the statementwe have to tell that by how many ways we construct a string of 3 digits from the decimal numbering system.So, For this purpose,let a three digits from 0 to 9.So, There are total digits are 10 and we have to construct three digits.so, we use permutation here:Permutation are one of the two different ways of grouping elements of a set into subsets. In a permutation, the elements of the subset are listed in a specific order.So, here become P(10,3)And according to formula it becomeP(10,3) = 10! / 7!P(10,3) = 10 * 9 * 8P(10,3) = 720.So, There are total 720 ways according to the permutation by which construct a string of 3 digits from the decimal numbering system.Learn more about permutation herehttps://brainly.com/question/1216161#SPJ4