How many ways are there to choose a 5-letter word from the 26-letter English alphabet with replacement, where words that are anagrams are considered the same

Answers

The words need not be English language words = 142506

What is Permutation and combination?

In mathematics, there are two alternative methods for dividing up a collection of components into subsets: combination and permutation. The subset’s components can be arranged in any sequence when used together. The components of the subset are arranged in a particular order in a permutation.

According to the given information:

If the word has 5 different letters then it is just 26-choose-5 or (26/5).

If the word has 4 different letters then it is just 26-choose-4 or (26/4)

have 4 options to choose which letter to duplicate twice.

This gives = 4*(26/4)

If the word has 3 different letters then it is just 26-choose-3 or (26/3).

you duplicate one of the three letters 3 times – 3 options for that, or you choose 2 letters and duplicate each one twice – again 3 options. In total this gives = 6*(26/3).

If the word has 2 different letters then it is just 26-choose-2 or (26/2).

The sets of 2 different letters and duplicate either one of the letters 4 times – 2 options; or duplicate one letter 2 times, and the other 3 times – again 2 options. In total this is = 4*(26/2).

The word has just 1 distinct letter you have = (26/1).

we get :

N = (26/5)+ 4*(26/4) + 6*(26/3) + 4*(26/2) + (26/1)

= 142506

The words need not be English language words = 142506

To know more about Permutation and combination visit:

wordsneed not beEnglish languagewords =142506What is Permutation and combination?alternativemethods for dividing up a collection ofcomponentsinto subsets:combinationandpermutation. The subset’scomponentscan be arranged in any sequence when used together. The components of the subset are arranged in a particular order in apermutation.## According to the given information:

wordsneed not beEnglish languagewords =142506Permutation and combinationvisit:#SPJ4