Question How many turns of wire are needed in a circular coil 13 cmcm in diameter to produce an induced emf of 5.6 VV

Answer: Number of turns of wire(N) = 3,036 turns (Approx) Explanation: Given: Diameter = 13 Cm emf = 5.6 v Note: The given question is incomplete, unknown information is as follow. Magnetic field increases = 0.25 T in 1.8 (Second) Find: Number of turns of wire(N) Computation: radius (r) = 13 / 2 = 6.5 cm = 0.065 m Area = πr² Area = (22/7)(0.065)(0.065) Area = 0.013278 m² So, emf = (N)(A)(dB / dt) 5.6 = (N)(0.013278)(0.25 / 1.8) 5.6 = (N)(0.013278)(0.1389) N = 3,036.35899 Number of turns of wire(N) = 3,036 turns (Approx) Log in to Reply

Answer:Number of turns of wire(N) = 3,036 turns (Approx)

Explanation:Given:Diameter = 13 Cm

emf = 5.6 v

Note:The given question is incomplete, unknown information is as follow.

Magnetic field increases = 0.25 T in 1.8 (Second)

Find:Number of turns of wire(N)

Computation:radius (r) = 13 / 2 = 6.5 cm = 0.065 m

Area = πr²

Area = (22/7)(0.065)(0.065)

Area = 0.013278 m²

So,

emf = (N)(A)(dB / dt)

5.6 = (N)(0.013278)(0.25 / 1.8)

5.6 = (N)(0.013278)(0.1389)

N = 3,036.35899

Number of turns of wire(N) = 3,036 turns (Approx)