Answer: 3.556x 10^-3mol Explanation: Using pH =-log [ H+], we can calculate the concentration of the hydrogen Ions. pH =-log [ H+], pH = 2.75 2.75 = -log[H+], taking antilog of both sides 10^ — 2.75 = [H+] [H+] =1. 778 x 10^-3M Now that we have the concentration and also knows the volume, we can use the relation Moles = concentration X volume = 1. 778 x 10^-3M x 2L = 3.56x 10^-3mol The moles of the hydrogen Ions is 3.56x 10^-3mol Log in to Reply

We are given: Volume = 2 L pH = 2.75 Finding the concentration required: we know that pH is just the negative log of the hydrogen ion concentration pH = -log[H⁺] we are given that the pH is 2.75 2.75 = -log[H⁺] log[H⁺] = -2.75 [multiplying both sides by -1] [tex]10^{log[H]} = 10^{-2.75}[/tex] [H⁺] = 1.78 * 10⁻³ Molar Number of moles of Hydrogen ions: [H⁺] = 1.78 * 10⁻³ Molar which means that there are 1.78 * 10⁻³ moles of hydrogen ions in 1 liter solution 1.78 * 10⁻³ moles / L multiplying and dividing by 2, we get: 3.56 * 10⁻³ moles / 2 L Hence we need 3.56 * 10⁻³ moles of hydrogen ions Log in to Reply

Answer:3.556x 10^-3mol

Explanation:Using pH =-log [ H+], we can calculate the concentration of the hydrogen Ions.

pH =-log [ H+], pH = 2.75

2.75 = -log[H+], taking antilog of both sides

10^ — 2.75 = [H+]

[H+] =1. 778 x 10^-3M

Now that we have the concentration and also knows the volume, we can use the relation

Moles = concentration X volume

= 1. 778 x 10^-3M x 2L = 3.56x 10^-3mol

The moles of the hydrogen Ions is

3.56x 10^-3molWe are given:Volume = 2 L

pH = 2.75

Finding the concentration required:we know that pH is just the negative log of the hydrogen ion concentration

pH = -log[H⁺]

we are given that the pH is 2.75

2.75 = -log[H⁺]

log[H⁺] = -2.75 [multiplying both sides by -1]

[tex]10^{log[H]} = 10^{-2.75}[/tex]

[H⁺] = 1.78 * 10⁻³ Molar

Number of moles of Hydrogen ions:[H⁺] = 1.78 * 10⁻³ Molar

which means that there are 1.78 * 10⁻³ moles of hydrogen ions in 1 liter solution

1.78 * 10⁻³ moles / L

multiplying and dividing by 2, we get:

3.56 * 10⁻³ moles / 2 LHence we need 3.56 * 10⁻³ moles of hydrogen ions