How many liters of a 35 percent salt solution must be mixed with 20 liters of a 70 percent salt solution to obtain a solution that is 45 percent salt

Answers

86 liters of 35% salt solution should be added to 20 liters of an 70% salt solution so that the resulting solution contains 45% salt solution .

For given question,

Let x be the quantity ( in liters ) of 35 percent salt solution added to 20 liters of an 70 percent salt solution so that the resulting solution contains 45 percent salt,

Thus,

Quantity of salt solution in 20 liters + Quantity of salt solution in x

= Quantity of salt solution in resultant mixture.

⇒ 70% of 20 + 35% of x = 45% of (20 + x )

⇒ 14 + (0.35x) = 0.45 × ( 12 + x )

⇒ 14 + 0.35x = 5.4 + 0.45x

⇒ 14 – 5.4 = 0.45x – 0.35x

⇒ 8.6 = 0.10x

⇒ x = 86 liters

Therefore, 86 liters of 35% salt solution should be added to 20 liters of an 70% salt solution so that the resulting solution contains 45% salt solution .

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