How many grams of FeCl3 are needed to make 1.5 L of a solution with a molarity of 0.450 M?

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How many grams of FeCl3 are needed to make 1.5 L of a solution with a molarity of 0.450 M?

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Moles=concentration x volume. 1.5/1000 multiply 0.450 = 6.75×10^-4

To find the mass of fecl3, we have the formula, mass=moles x molar mass. 6.75×10^-4 x (55.8+35.5 x 3). = 0.1096g

Not sure tho if i did it right