Question How many elements are in the union of three pairwise disjoint sets if the sets contain 10, 15, and 25 elements

The union of three pairwise disjoint sets containing 10, 15, and 25 elements will contain 50 elements. In the question, we are asked for the number of elements in the union of three pairwise disjoint sets if the sets contain 10, 15, and 25 elements. We assume the three sets to be A, B, and C, respectively. Thus, we are given that n(A) = 10, n(B) = 15, and n(C) = 25. Given that the three sets are pairwise disjoint, we know that the intersection of sets will be a null set, that is, A ∩ B = B ∩ C = C ∩ A = A ∩ B ∩ C = {}. Thus, we can write that, n(A ∩ B) = 0, n(B ∩ C) = 0, n(C ∩ A) = 0, and n(A ∩ B ∩ C) = 0. Now, for the union of three sets, we need to know the formula: n(A ∪ B ∪ C) = n(A) + n(B) + n(C) – n(A ∩ B) – n(B ∩ C) – n(C ∩ A) + n(A ∩ B ∩ C). Substituting the values, we get: n(A ∪ B ∪ C) = 10 + 15 + 25 – 0 – 0 – 0 + 0, or, n(A ∪ B ∪ C) = 50. Thus, the union of three pairwise disjoint sets containing 10, 15, and 25 elements will contain 50 elements. Learn more about sets at https://brainly.com/question/8823120 #SPJ4 Reply

Answer: 50 elements are in the union of three pairwise disjoint sets if the sets contain 10, 15, and 25 elements Step-by-step explanation: Let A, B and C be the three sets. We are given that the sets are pairwise disjoint. Therefore, we can write : n(A)=10 n(B)=15 n(C)=25 n(A∩B)=0 n(B∩C)=0 n(C∩A)=0 n(A∩B∩C)=0 Number of elements in the union of these sets will be : n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(C∩A)+n(A∩B∩C) Putting all the given values in the formula above, we get n(A∪B∪C)=10+15+25−0−0−0+0 ⇒n(A∪B∪C)=50 What is disjoint set? Two sets are said to be disjoint if they have no element in common. Equivalently, disjoint sets are sets whose intersection is the empty set. Learn more about disjoint sets here: https://brainly.ph/question/39533 Reply

unionof threepairwise disjoint setscontaining 10, 15, and 25 elements will contain50 elements.elementsin theunionof three pairwisedisjoint setsif thesetscontain 10, 15, and 25 elements.disjoint, we know that theintersectionof sets will be a null set, that is,unionof three sets, we need to know the formula:unionof threepairwise disjoint setscontaining 10, 15, and 25 elements will contain50 elements.setsatAnswer:50elements are in the union of three pairwisedisjoint setsif thesetscontain 10, 15, and 25 elementsStep-by-step explanation:sets. We are given that thesetsare pairwisedisjoint. Therefore, we can write :setswill be :n(A∪B∪C)=50disjoint set?setsare said to bedisjointif they have no element in common. Equivalently,disjoint setsaresetswhose intersection is the emptyset.disjoint setshere: https://brainly.ph/question/39533