Question

how 4-digit positive integers have four differennt digits, where the leading digit is not zero, the integer is a multiple of 5, and 5 is the largets digt

Answers

  1. Answer:
    There are 9 possible thousands digits, because 0 cannot be the leading digit.
    There are 2 possible ones digits, 0 and 5.
    If the ones digit is 5:
    There are 5 possible thousands digits: 1, 2, 3, and 4.For each possible thousands digit, there are 5 possible hundreds digits. (We used one of the digits above to be the thousands digit, but 0 is a possible hundreds digit.)For each possible pair of thousands-and-hundreds digits, there are 4 possible tens digits.
    So there are 5 x 5 x 4 = 100 possible 4-digit numbers that end in 5 with no repeated digit and no digit larger than 5.
    If the ones digit is 0:
    There are 5 possible thousands digits.For each possible thousands digit, there are 4 possible hundreds digits.For each possible pair of thousands-and-hundreds digits, there are 6 possible tens digits.
    So there are 5 x 4 x 6 = 120 possible 4-digit numbers that end in 0 with no repeated digit and no digit larger than 5.
    100+120=220
    Answer: 220 possible numbers.

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