Question Help Quickly Please Calculate the critical angle between diamond (n = 2.42) and quartz (n = 1.46)? 23° 37° 52° 60°

Answer: Critical angle for diamond and quartz is given as [tex]\theta_c = 37.1 degree[/tex] Explanation: As we know that the critical angle is the angle of incidence at which the light ray will refract at 90 degree angle so as per law of refraction we will have [tex]n_1 sin\theta_1 = n_2 sin\theta_2[/tex] here we know that [tex]n_1 = 2.42[/tex] [tex]n_2 = 1.46[/tex] [tex]\theta_1 = \theta_c[/tex] [tex]\theta_2 = 90[/tex] now we have [tex]2.42 sin\theta_c = 1.46\times 1[/tex] so we have [tex]\theta_c = 37.1 degree[/tex] Log in to Reply

Answer:## Critical angle for diamond and quartz is given as

## [tex]\theta_c = 37.1 degree[/tex]

Explanation:As we know that the critical angle is the angle of incidence at which the light ray will refract at 90 degree angle

so as per law of refraction we will have

[tex]n_1 sin\theta_1 = n_2 sin\theta_2[/tex]

here we know that

[tex]n_1 = 2.42[/tex]

[tex]n_2 = 1.46[/tex]

[tex]\theta_1 = \theta_c[/tex]

[tex]\theta_2 = 90[/tex]

now we have

[tex]2.42 sin\theta_c = 1.46\times 1[/tex]

so we have

[tex]\theta_c = 37.1 degree[/tex]