Question Help Quickly Please Calculate the critical angle between diamond (n = 2.42) and quartz (n = 1.46)? 23° 37° 52° 60°
Answer: Critical angle for diamond and quartz is given as [tex]\theta_c = 37.1 degree[/tex] Explanation: As we know that the critical angle is the angle of incidence at which the light ray will refract at 90 degree angle so as per law of refraction we will have [tex]n_1 sin\theta_1 = n_2 sin\theta_2[/tex] here we know that [tex]n_1 = 2.42[/tex] [tex]n_2 = 1.46[/tex] [tex]\theta_1 = \theta_c[/tex] [tex]\theta_2 = 90[/tex] now we have [tex]2.42 sin\theta_c = 1.46\times 1[/tex] so we have [tex]\theta_c = 37.1 degree[/tex] Log in to Reply
Answer:
Critical angle for diamond and quartz is given as
[tex]\theta_c = 37.1 degree[/tex]
Explanation:
As we know that the critical angle is the angle of incidence at which the light ray will refract at 90 degree angle
so as per law of refraction we will have
[tex]n_1 sin\theta_1 = n_2 sin\theta_2[/tex]
here we know that
[tex]n_1 = 2.42[/tex]
[tex]n_2 = 1.46[/tex]
[tex]\theta_1 = \theta_c[/tex]
[tex]\theta_2 = 90[/tex]
now we have
[tex]2.42 sin\theta_c = 1.46\times 1[/tex]
so we have
[tex]\theta_c = 37.1 degree[/tex]