Answers

1. Answer:

   Step-by-step explanation:

   Select the correct answer from each drop-down menu. A number is 5 more than 3 times another number. The sum of the two numbers is 33. As an equation, this is written x + 3x + 5 = 33, where x represents the smaller number. Plugin the numbers from the set {3, 5, 7, 9} to find the value of x. The value of x that holds true for the equation is 7. So, the smaller number is 7 and the larger number is 26 .

   Find the value of x in x + 3x + 5 = 33, using {3, 5, 7, 9}

   3:

   x + 3x + 5 = 33

   3 + 3(3) + 5 = 33

   3 + 9 + 5 = 33

   12 + 5 = 33

   17 = 33

   This is false, 17 does not equal to 33. <== wrong

   5:

   x + 3x + 5 = 33

   5 + 3(5) + 5 = 33

   5 + 15 + 5 = 33

   20 + 5 = 33

   25 = 33

   This is false, 25 does not equal to 33. <== wrong

   7:

   x + 3x + 5 = 33

   7 + 3(7) + 5 = 33

   7 + 21 + 5 = 33

   7 + 26= 33 <== (smaller number = 7, larger number = 26)

   33 = 33

   This is true, 33 does equal to 33. <== correct

   9:

   x + 3x + 5 = 33

   9 + 3(9) + 5 = 33

   9 + 27 + 5 = 33

   36 + 5 = 33

   41 = 33

   This is false, 41 does not equal to 33. <== wrong

   Not that we know that x = 7 (the smaller number), we need to find 3x (the larger number)

   3x

   3(7) = 21

   Now, we add that to our original 5

   21 + 5 = 26

   Therefore, the smaller number is 7, while the larger number is 26.

   Hope this helps!

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