he students a, b, and c have 10%, 20%, and 30% chance of independently solving a certain maths problem. if they all try independen

he students a, b, and c have 10%, 20%, and 30% chance of independently solving a certain maths problem. if they all try independently of one another, what is the probability that at least one of them will solve the problem?

1 thought on “he students a, b, and c have 10%, 20%, and 30% chance of independently solving a certain maths problem. if they all try independen”

  1. Probability that at least one of them(from A, B or C)  will solve the problem is 0.496
    The likelihood that A, B, and C each find a solution to the problem is 0.1, 0.2, and 0.3, respectively.
    In general, the likelihood that none of them will be able to solve it is the complement of the probability that at least one of them will. Hence
    P(at least one) = 1-P(none)
    The probability that none of them will solve it is 0.9*0.8*0.7 (the probability that A does not solve the problem and B does not solve the problem and neither does C). Take the complement, and you’ve got your answer:
    P(A or B or C solves the problem) = 1- (0.9*0.8*0.7)
         = 1- 0.504
         = 0.496
    So, the probability that at least one of them will solve the problem is 0.496 or 49.6%
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