Question

He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0. which best describes the reasonableness of the student’s solution? his solution for x is correct and his explanation of the extraneous solution is reasonable. his solution for x is correct, but in order for 6 to be an extraneous solution, both denominators have to result in 0 when 6 is substituted for x. his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x. his solution for x is incorrect. when solved correctly, there are no extraneous solutions.

Answers

  2. The question is incomplete. Completed question is given below the answer.
    His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.
    Given  
    Then the solution follows thus:
    Step 1: 8(x – 4) = 2(x + 2)
    Step 2: 4(x – 4) = (x + 2)
    Step 3: 4x – 16 = x + 2
    Step 4: 3x = 18
    Step 5: x = 6
    It can be seen that his solution is correct. But 6 is not an extraneous solution.
    An extraneous solution is a solution to an equation that emerges from the process of solving the problem but is not a valid solution to the original problem.
    When 6 is substituted into the original equation, the original equation holds.
    Therefore, his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.
    Learn more about extraneous solution here: https://brainly.com/question/3751209
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    Completed question:-
    A student solves the following equation for all possible values of x:His solution is as follows:
    Step 1: 8(x – 4) = 2(x + 2)
    Step 2: 4(x – 4) = (x + 2)
    Step 3: 4x – 16 = x + 2
    Step 4: 3x = 18
    Step 5: x = 6
    He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0.
    Which best describes the reasonableness of the student’s solution?
    His solution for x is correct and his explanation of the extraneous solution is reasonable.
    His solution for x is correct, but in order for 6 to be an extraneous solution, both denominators have to result in 0 when 6 is substituted for x.
    His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.
    His solution for x is incorrect. When solved correctly, there are no extraneous solutions.

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