Given 12 different 2-digit numbers, show that one can choose two of them such that their difference is a two-digit number with identical first and second digit
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Step-by-step explanation:there are 91 2-digit numbers : 10 ..99and there are 9 2-digit numbers with identical first and second digit : 11, 22, 33, 44, 55, 66, 77, 88, 9999 has to be excluded, because there are no 2 2- digit numbers that I can subtract from each other and get 99.so, e are dealing with 8 possibilities.88 = 99-1198-1077 = 99-2298-2197-20…78-166 = 99-3398-32…67-1…11 = 99-8898-87…12-1all the double- digit numbers are 11 apart. so, by picking 12 numbers, I have to have at least one that I can combine with one of the other 11 to get a double-digit number.