For what value(s) of k will the relation not be a function?
#1: A = {(k^2, 16), (4k, 32)}
#2: B = {(k^2-5k, 10), (k+7, 4)}
#3: R = {(k^3-5k^2+3k, -5), (-k, 4)}
#4: S = {(|k+1|+2, 4), (8, 7)}
Will give 100 points and Brainliest!
For what value(s) of k will the relation not be a function?
#1: A = {(k^2, 16), (4k, 32)}
#2: B = {(k^2-5k, 10), (k+7, 4)}
#3: R = {(k^3-5k^2+3k, -5), (-k, 4)}
#4: S = {(|k+1|+2, 4), (8, 7)}
Will give 100 points and Brainliest!
Answer:
Step-by-step explanation:
The relation is not a function when x -value is same but y- values are different.
#1
#2
#3
#4